From: Yumei Huang <yuhuang@redhat.com>
To: Stefano Brivio <sbrivio@redhat.com>
Cc: passt-dev@passt.top, david@gibson.dropbear.id.au
Subject: Re: [PATCH v6 4/4] tcp: Update data retransmission timeout
Date: Tue, 28 Oct 2025 16:09:03 +0800 [thread overview]
Message-ID: <CANsz47=kg4z7w_O77YWCTP53Le_bMLS-6G0xjj23XNTjRqtEXg@mail.gmail.com> (raw)
In-Reply-To: <20251024010438.16e19757@elisabeth>
On Fri, Oct 24, 2025 at 7:04 AM Stefano Brivio <sbrivio@redhat.com> wrote:
>
> On Fri, 17 Oct 2025 14:28:38 +0800
> Yumei Huang <yuhuang@redhat.com> wrote:
>
> > Use an exponential backoff timeout for data retransmission according
> > to RFC 2988 and RFC 6298. Set the initial RTO to one second as discussed
> > in Appendix A of RFC 6298.
> >
> > Also combine the macros defining the initial RTO for both SYN and ACK.
> >
> > Signed-off-by: Yumei Huang <yuhuang@redhat.com>
> > Reviewed-by: David Gibson <david@gibson.dropbear.id.au>
> > ---
> > tcp.c | 27 ++++++++++++---------------
> > 1 file changed, 12 insertions(+), 15 deletions(-)
> >
> > diff --git a/tcp.c b/tcp.c
> > index 9385132..dc0ec6c 100644
> > --- a/tcp.c
> > +++ b/tcp.c
> > @@ -179,16 +179,14 @@
> > *
> > * Timeouts are implemented by means of timerfd timers, set based on flags:
> > *
> > - * - SYN_TIMEOUT_INIT: if no ACK is received from tap/guest during handshake
> > - * (flag ACK_FROM_TAP_DUE without ESTABLISHED event) within this time, resend
> > - * SYN. It's the starting timeout for the first SYN retry. If this persists
> > - * for more than TCP_MAX_RETRIES or (tcp_syn_retries +
> > - * tcp_syn_linear_timeouts) times in a row, reset the connection
> > - *
> > - * - ACK_TIMEOUT: if no ACK segment was received from tap/guest, after sending
> > - * data (flag ACK_FROM_TAP_DUE with ESTABLISHED event), re-send data from the
> > - * socket and reset sequence to what was acknowledged. If this persists for
> > - * more than TCP_MAX_RETRIES times in a row, reset the connection
> > + * - RTO_INIT: if no ACK segment was received from tap/guest, either during
> > + * handshake (flag ACK_FROM_TAP_DUE without ESTABLISHED event) or after
> > + * sending data (flag ACK_FROM_TAP_DUE with ESTABLISHED event), re-send data
> > + * from the socket and reset sequence to what was acknowledged. This is the
> > + * timeout for the first retry, in seconds. If this persists too many times
> > + * in a row, reset the connection: TCP_MAX_RETRIES for established
> > + * connections, or (tcp_syn_retries + tcp_syn_linear_timeouts) during the
> > + * handshake.
> > *
> > * - FIN_TIMEOUT: if a FIN segment was sent to tap/guest (flag ACK_FROM_TAP_DUE
> > * with TAP_FIN_SENT event), and no ACK is received within this time, reset
> > @@ -342,8 +340,7 @@ enum {
> > #define WINDOW_DEFAULT 14600 /* RFC 6928 */
> >
> > #define ACK_INTERVAL 10 /* ms */
> > -#define SYN_TIMEOUT_INIT 1 /* s */
> > -#define ACK_TIMEOUT 2
> > +#define RTO_INIT 1 /* s, RFC 6298 */
> > #define FIN_TIMEOUT 60
> > #define ACT_TIMEOUT 7200
> >
> > @@ -588,13 +585,13 @@ static void tcp_timer_ctl(const struct ctx *c, struct tcp_tap_conn *conn)
> > } else if (conn->flags & ACK_FROM_TAP_DUE) {
> > if (!(conn->events & ESTABLISHED)) {
> > if (conn->retries < c->tcp.syn_linear_timeouts)
> > - it.it_value.tv_sec = SYN_TIMEOUT_INIT;
> > + it.it_value.tv_sec = RTO_INIT;
> > else
> > - it.it_value.tv_sec = SYN_TIMEOUT_INIT <<
> > + it.it_value.tv_sec = RTO_INIT <<
> > (conn->retries - c->tcp.syn_linear_timeouts);
> > }
> > else
> > - it.it_value.tv_sec = ACK_TIMEOUT;
> > + it.it_value.tv_sec = RTO_INIT << conn->retries;
>
> Same as on 3/4, but here it's clearly more convenient: just assign
> RTO_INIT, and multiply as needed in the if / else clauses.
I guess we can't just assign RTO_INIT. Maybe assign it only when
retries==0, otherwise multiply as it.it_value.tv_sec <<=1. But it
seems more complicated. What do you think?
>
> > } else if (CONN_HAS(conn, SOCK_FIN_SENT | TAP_FIN_ACKED)) {
> > it.it_value.tv_sec = FIN_TIMEOUT;
> > } else {
>
> The rest of the series looks good to me.
>
> It might be slightly more practical to factor in directly the RTO
> clamp, and I don't think it's complicated now that you have the helper
> from 2/4, but it's not a strong preference from my side, as the series
> makes sense in any case.
Reading tcp_rto_max_ms can be easy with the helper. My concern is
about the way we get the total time for retries.
I used to do it like this in v2,
https://archives.passt.top/passt-dev/20251010074700.22177-4-yuhuang@redhat.com/:
+#define RETRY_ELAPSED(timeout_init, retries) \
+ ((timeout_init) * ((1 << ((retries) + 1)) - 2))
Though the formula is not quite right, we could refine it as below:
#define RETRY_ELAPSED(retries) ((RTO_INIT) * ((1 << ((retries) + 1)) - 1))
Does it make sense to get the time this way?
>
> --
> Stefano
>
--
Thanks,
Yumei Huang
next prev parent reply other threads:[~2025-10-28 8:09 UTC|newest]
Thread overview: 44+ messages / expand[flat|nested] mbox.gz Atom feed top
2025-10-17 6:28 [PATCH v6 0/4] Retry SYNs for inbound connections Yumei Huang
2025-10-17 6:28 ` [PATCH v6 1/4] tcp: Rename "retrans" to "retries" Yumei Huang
2025-10-17 6:28 ` [PATCH v6 2/4] util: Introduce read_file() and read_file_integer() function Yumei Huang
2025-10-19 10:07 ` Stefano Brivio
2025-10-21 9:32 ` Yumei Huang
2025-10-21 21:50 ` Stefano Brivio
2025-10-22 0:51 ` David Gibson
2025-10-22 8:42 ` Yumei Huang
2025-10-22 0:55 ` Yumei Huang
2025-10-23 23:04 ` Stefano Brivio
2025-10-24 3:16 ` David Gibson
2025-10-24 6:05 ` Yumei Huang
2025-10-28 7:11 ` Yumei Huang
2025-10-28 11:43 ` Stefano Brivio
2025-10-17 6:28 ` [PATCH v6 3/4] tcp: Resend SYN for inbound connections Yumei Huang
2025-10-22 1:16 ` David Gibson
2025-10-22 1:30 ` Yumei Huang
2025-10-22 2:26 ` David Gibson
2025-10-23 23:04 ` Stefano Brivio
2025-10-24 3:30 ` David Gibson
2025-10-24 8:37 ` Stefano Brivio
2025-10-24 10:55 ` David Gibson
2025-10-27 3:37 ` Yumei Huang
2025-10-27 6:49 ` Stefano Brivio
2025-10-28 7:43 ` Yumei Huang
2025-10-28 11:44 ` Stefano Brivio
2025-10-29 2:31 ` Yumei Huang
2025-10-17 6:28 ` [PATCH v6 4/4] tcp: Update data retransmission timeout Yumei Huang
2025-10-22 1:19 ` David Gibson
2025-10-22 8:40 ` Yumei Huang
2025-10-23 23:04 ` Stefano Brivio
2025-10-28 8:09 ` Yumei Huang [this message]
2025-10-28 11:44 ` Stefano Brivio
2025-10-28 11:54 ` Stefano Brivio
2025-10-29 3:06 ` Yumei Huang
2025-10-29 4:38 ` Stefano Brivio
2025-10-29 5:11 ` Yumei Huang
2025-10-29 7:09 ` Stefano Brivio
2025-10-29 7:32 ` Yumei Huang
2025-10-29 7:39 ` Stefano Brivio
2025-10-29 8:59 ` Yumei Huang
2025-10-29 12:18 ` Stefano Brivio
2025-10-30 8:25 ` Yumei Huang
2025-10-30 8:51 ` Stefano Brivio
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