On Tue, Nov 19, 2024 at 08:53:44PM +0100, Stefano Brivio wrote: > RFC 9293, 3.8.4 says: > > Implementers MAY include "keep-alives" in their TCP implementations > (MAY-5), although this practice is not universally accepted. Some > TCP implementations, however, have included a keep-alive mechanism. > To confirm that an idle connection is still active, these > implementations send a probe segment designed to elicit a response > from the TCP peer. Such a segment generally contains SEG.SEQ = > SND.NXT-1 and may or may not contain one garbage octet of data. If > keep-alives are included, the application MUST be able to turn them > on or off for each TCP connection (MUST-24), and they MUST default to > off (MUST-25). > > but currently, tcp_data_from_tap() is not aware of this and will > schedule a fast re-transmit on the second keep-alive (because it's > also a duplicate ACK), ignoring the fact that the sequence number was > rewinded to SND.NXT-1. > > ACK these keep-alive segments, reset the activity timeout, and ignore > them for the rest. > > At some point, we could think of implementing an approximation of > keep-alive segments on outbound sockets, for example by setting > TCP_KEEPIDLE to 1, and a large TCP_KEEPINTVL, so that we send a single > keep-alive segment at approximately the same time, and never reset the > connection. That's beyond the scope of this fix, though. > > Reported-by: Tim Besard > Link: https://github.com/containers/podman/discussions/24572 > Signed-off-by: Stefano Brivio > --- > tcp.c | 14 ++++++++++++++ > 1 file changed, 14 insertions(+) > > diff --git a/tcp.c b/tcp.c > index f357920..1eb85bb 100644 > --- a/tcp.c > +++ b/tcp.c > @@ -1763,6 +1763,20 @@ static int tcp_data_from_tap(const struct ctx *c, struct tcp_tap_conn *conn, > continue; > > seq = ntohl(th->seq); > + if (SEQ_LT(seq, conn->seq_from_tap) && len <= 1) { > + flow_trace(conn, > + "keep-alive sequence: %u, previous: %u", > + seq, conn->seq_from_tap); > + > + tcp_send_flag(c, conn, ACK); > + tcp_timer_ctl(c, conn); > + > + if (p->count == 1) > + return 1; I'm not sure what this test is for. Shouldn't the continue be sufficient? > + > + continue; > + } > + > ack_seq = ntohl(th->ack_seq); > > if (th->ack) { -- David Gibson (he or they) | I'll have my music baroque, and my code david AT gibson.dropbear.id.au | minimalist, thank you, not the other way | around. http://www.ozlabs.org/~dgibson